Therefore, Paul has 1/4 of the total number of gold coins, i.e. Only the first result will result in a final victory for Paul, and the other 3 results will result in a final victory for Mel. 3/412=9.Īccording to Fermat: If you play two games, it is completely decisive, and its two games will have four results: (Paul wins, Paul wins), (Paul wins, Mel wins), (Mel wins, Paul wins), and (Mel wins, Mel wins). Similarly, Mel also gets half of the two probabilities, i.e. Since the probability of winning this game is equal, Paul should get half of the two probabilities, i.e. Pascal thought: if another game may Paul win, may Mel win, if Paul wins, then two people win two games each, should get half of the total gold coins (recorded as 1/2) if Mel wins, then he won 3 games, can get all the gold coins (recorded as 1), Paul is not allowed to gold coins (recorded as 0). This incident aroused the interest of mathematicians such as Pascal and Fermat, and they began to study how the 12 gold coins should be distributed. Since the two of them could not reach an agreement, they asked Pascal and Fermat, the mathematicians of the time, for advice. But Mel thinks that this is unfair to him, he thinks that if the gambling continues, he is more likely to win than Paul, and he should get all 12 coins. 4 gold coins, and Mel should get 2/3 of the total, i.e. Paul thought that, according to the number of games they won, he should get 1/3 of the total, i.e. So, they discussed how the 12 gold coins should be divided. The gambling was interrupted by an incident in which none of them won 3 games, at which point Paul had won one game and Mel had won two games. They each took out 6 gold coins to play dice beforehand and agreed that whoever won 3 games first would get 12 gold coins. In 1951, the gamblers Mel and Paul bet money. Probability applied to gambling Introduction to Gambling
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